Kuta software infinite algebra 1 solving systems of inequalities

©TI2z0z1G2ZkKSuXtxapgSdoyfbtTwAarrteUsLHLmCE.HBOA9lMlIyrNi8glhJtOsRFrpessSeerJvJe8dk.Hb9M0aYdqeWrwPiYtNhkeIqn6f7i3nuistne2HAhlQgee4byrFakz16.WWorksheet by Kuta Software LLCKuta Software - Infinite Algebra 1Name___________________________________Period____Date________________Solving Systems of InequalitiesSketch the solution to each system of inequalities.1) yx yx xy2) yx yx xy3) yx yx xy4) x yx xy

  • School Long Branch High
  • Course Title MATH Linear Alg
  • Type

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  • Uploaded By kishan121
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Kuta software infinite algebra 1 solving systems of inequalities

Unformatted text preview: Kuta Software - Infinite Algebra 1 Name___________________________________ Solving Systems of Inequalities Date________________ Period____ Sketch the solution to each system of inequalities. 5 x−2 2 1 y≥ x+2 2 5 x+2 2 1 y≥ x−2 2 1) y ≤ 2) y ≥ 5 5 4 4 3 3 2 2 1 1 −5 −4 −3 −2 −1 0 1 2 3 4 5 −5 −4 −3 −2 −1 0 −2 4 5 1 2 3 4 5 −4 −5 3 −3 −4 2 −2 −3 1 −5 4) y < −3 y ≥ 4x + 1 1 x+2 2 y > 3x − 3 3) y ≤ 5 5 4 4 3 3 2 2 1 1 −5 −4 −3 −2 −1 0 −5 −4 −3 −2 −1 0 1 2 3 4 5 −2 −2 −3 −3 −4 −4 −5 −5 -1- 1 x−1 3 4 y≤ x+2 3 1 6) y > − x − 3 3 5 y≤ x+3 3 5) y ≥ 5 5 4 4 3 3 2 2 1 1 −5 −4 −3 −2 −1 0 1 2 3 4 5 −5 −4 −3 −2 −1 0 −2 4 5 1 2 3 4 5 1 2 3 4 5 −4 −5 3 −3 −4 2 −2 −3 1 −5 7) 2 x + y < −3 2 x − y ≤ −1 8) 3 x + y > −3 x + 2y < 4 5 5 4 4 3 3 2 2 1 1 −5 −4 −3 −2 −1 0 1 2 3 4 5 −5 −4 −3 −2 −1 0 −2 −2 −3 −3 −4 −4 −5 −5 9) x + y ≥ −3 5 x − y ≤ −3 10) 3 x − y ≥ −1 x + y ≤ −3 5 5 4 4 3 3 2 2 1 1 −5 −4 −3 −2 −1 0 1 2 3 4 5 −5 −4 −3 −2 −1 0 −2 −2 −3 −3 −4 −4 −5 −5 -2- Kuta Software - Infinite Algebra 1 Name___________________________________ Solving Systems of Inequalities Date________________ Period____ Sketch the solution to each system of inequalities. 5 x−2 2 1 y≥ x+2 2 5 x+2 2 1 y≥ x−2 2 1) y ≤ 2) y ≥ 5 5 4 4 3 3 2 2 1 1 −5 −4 −3 −2 −1 0 1 2 3 4 5 −5 −4 −3 −2 −1 0 −2 4 5 1 2 3 4 5 −4 −5 3 −3 −4 2 −2 −3 1 −5 4) y < −3 y ≥ 4x + 1 1 x+2 2 y > 3x − 3 3) y ≤ 5 5 4 4 3 3 2 2 1 1 −5 −4 −3 −2 −1 0 −5 −4 −3 −2 −1 0 1 2 3 4 5 −2 −2 −3 −3 −4 −4 −5 −5 -1- 1 x−1 3 4 y≤ x+2 3 1 6) y > − x − 3 3 5 y≤ x+3 3 5) y ≥ 5 5 4 4 3 3 2 2 1 1 −5 −4 −3 −2 −1 0 1 2 3 4 5 −5 −4 −3 −2 −1 0 −2 4 5 1 2 3 4 5 1 2 3 4 5 −4 −5 3 −3 −4 2 −2 −3 1 −5 7) 2 x + y < −3 2 x − y ≤ −1 8) 3 x + y > −3 x + 2y < 4 5 5 4 4 3 3 2 2 1 1 −5 −4 −3 −2 −1 0 1 2 3 4 5 −5 −4 −3 −2 −1 0 −2 −2 −3 −3 −4 −4 −5 −5 9) x + y ≥ −3 5 x − y ≤ −3 10) 3 x − y ≥ −1 x + y ≤ −3 5 5 4 4 3 3 2 2 1 1 −5 −4 −3 −2 −1 0 1 2 3 4 5 −5 −4 −3 −2 −1 0 −2 −2 −3 −3 −4 −4 −5 −5 -2- ...
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How do you solve systems of inequalities?

Step 1: Solve the inequality for y. ... .
Step 2: Graph the boundary line for the inequality. ... .
Step 3: Shade the region that satisfies the inequality. ... .
Step 4: Solve the second inequality for y. ... .
Step 5: Graph the boundary line for the second inequality. ... .
Step 6: Shade the region that satisfies the second inequality..

How do you solve systems of linear inequalities by graphing?

SOLVE A SYSTEM OF LINEAR INEQUALITIES BY GRAPHING..
Graph the first inequality. Graph the boundary line. ... .
On the same grid, graph the second inequality. Graph the boundary line. ... .
The solution is the region where the shading overlaps..
Check by choosing a test point..

What are the system of inequalities?

A system of inequalities is a set of two or more inequalities in one or more variables. Systems of inequalities are used when a problem requires a range of solutions, and there is more than one constraint on those solutions. Leon is the manager of a textile factory.