Answer: Step-by-step explanation: Since, lines l and m are parallel and a transverse is intersecting these lines. 5). (9x + 2)° = 119° [Alternate intrior angles] 9x = 117 ⇒ x = 13 6). (12x - 8)° + 104° = 180° 12x = 180 - 96 x = ⇒ x = 7 7). (5x + 7) = (8x - 71) [Alternate exterior angles] 8x - 5x = 71 + 7 3x = 78 x = 26 8). (4x - 7) = (7x - 61) [Corresponding angles] 7x - 4x = -7 + 61 3x = 54 x = 18 9). (9x + 25) = (13x - 19) [Corresponding angles] 13x - 9x = 25 + 19 4x = 44 x = 11 (13x - 19)° + (17y + 5)° = 180°[Linear pair of angles are supplementary] (13×11) - 19 + 17y + 5 = 180 129 + 17y = 180 17y = 180 - 129 y = 3 10). (3x - 29) + (8y + 17) = 180 [linear pair of angles are supplementary] 3x + 8y = 180 + 12 3x + 8y = 192 -----(1) (8y + 17) = (6x - 7) [Alternate exterior angles] 6x - 8y = 24 3x - 4y = 12 -----(2) Equation (1) - equation (2) (3x + 8y) - (3x - 4y) = 192 - 12 12y = 180 y = 15 From equation (1), 3x + 8(15) = 192 3x + 120 = 192 x = 24 11). (3x + 49)° = (7x - 23)° [Corresponding angles] 7x - 3x = 49 + 23 4x = 72 ⇒ x = 18 (11y - 1)° = (3x)° [Corresponding angles] 11y = 3×18 + 1 11y = 55 ⇒ y = 5 12). (5x - 38)° = (3x - 4)° [Corresponding angles] 5x - 3x = 38 - 4 2x = 34 x = 17 (7y - 20)° + (5x - 38)° + 90° = 180° [Sum of interior angles of a triangle = 180°] 7y + 5x - 58 = 90 5x + 7y = 148 5×17 + 7y = 148 85 + 7y = 148 7y = 148 - 85 y = This preview shows page 1 - 2 out of 2 pages. Name:{m~lyTvrnrnoloDate:lJiIIa!?.IPer:_..__Unff3:Parallel&PerpendicularLinesDHomework2:ParallelLinesCutbyaTransversal[••ThisIsa 2-page document!••1.Ifm LB=23°. find each measure. Give your reasoning.a.mL l=157°b.mL2=~30C.mL3 =157°d.mL4 =~.30e.mL5=151uf.mL6=~30g.mL7=157° 2.IfmL9=97°andmLl2 =114°,find each measure. Get answer to your question and much more 3.IfmL2=98°,mL3=23°andmLB=7CJ',find each measure.\i~o,O0_μ'.L.H"'7-~---"'7"Cc;---;____,__ Get answer to your question and much more 4.IfmL3=54°,find each measure.[''f';')t0, \mLlO=5i0 Get answer to your question and much more End of preview. Want to read all 2 pages? Upload your study docs or become a Course Hero member to access this document |